Different bugs have different reactions to the flame. However, the ropes do not burn at constant ratesthere are spots where they. Each rope will take exactly 1 hour to burn all the way through. There’s a catch! The fire only burns upwards, leaving you to tilt and turn your phone to keep your flame alive!Īs you progress through the levels, you’ll encounter bugs crawling along the rope. You have two ropes coated in an oil to help them burn. All you have to do is feed the fire!īurn the Rope is a challenging game where you try to burn as much rope as you can in each level. Burn the Rope is a unique game for the pyro in all of us. 'Burn the Rope has the inventiveness that makes the best puzzle games interesting.' - SlideToPlayįrom the team that brought you Thumpies –‘game that reinvented the rhythm genre’ here comes one of the most original games this year. 'The fire physics in the game are excellent' - AppSafari 'Burn the Rope is a pretty great experience' - TouchArcade So, for 4 ropes, we agree that there are 34 (23+11) different times that can be measured.

The two numbers below the two sets are the lengths of the sets. The second set contains all of the intermediate start/stop pairs. For each number, the first set assumes the timer starts at time 0. I also wrote a Python program to solve this. The time elapsed between when we start and stop the timer is 5/8. Here are all the steps in the order in which they occur:ġ) simultaneously light A at both ends and light B at one end.Ģ) when A burns out: start the timer, light B at other end, light C at one end.ģ) when B burns out: light C at other end. Suppose the ropes are labeled A, B, and C. We can now assemble all these pieces of information to construct the solution. Now we have measured 1/4… and all we needed to do was be able to measure 1/2.ģ) 1/2 comes from S1 and is found by starting the timer, lighting the rope at both ends, and stopping the timer once the rope is burnt. Since there is 1/2 left of the rope and we just lit the second end, it will burn for 1/4. Assuming we are able to measure 1/2, we do the following: light the rope at one end, wait 1/2, light the other end, and start the timer. So we have measured 5/8… and all we needed to do was be able to measure 1/4.Ģ) 1/4 comes from (1-1/2)/2, where 1/2 belongs to S1. Since there is 3/4 left of the rope and we just lit the second end, it will burn for 3/8. Assuming we are able to measure 1/4, we do the following: start the timer, light the rope at one end, wait 1/4, then light the other end.

As you’ll see, it should be possible to write a recursive computer program that spits out the recipes for each possible number. This may seem like a lot of work but it’s very formulaic. We can construct the 5/8 solution by working in reverse. I interpreted “measure” to mean that it’s possible to use a stopwatch that you start and top at specified events and the time indicated on the stopwatch would be the “measured” time. Note: my solution is incomplete (see comments below!) Author Laurent Posted on FebruFebruCategories The Riddler Tags recursion, Riddler This measures $| au-1|$ or $| au- frac$ hours. Starting at the first beep, light one side (or both sides) of the rope and measure the time elapsed between when the rope is fully burnt and the second beep.Measure the time elapsed between both beeps (don’t use the rope at all).Using a single rope, what new intervals of time can we now measure? There are several things we can do: We can imagine this as two beeps that occur exactly $ au$ apart. Suppose we the ability to measure a time interval $ au$ and nothing else. Let’s start by answering simple question that will give us the key insight needed to solve the problem: My solution uses a recursive approach: adding one rope at a time and seeing how the set of measurable time intervals increases.

You have to burn the rope 2